[BNM] Flash "if" statement @

[Seb L]

Try :

if (emailAddress.indexOf("@")>=0)  instead of if (emailAddress.indexOf("@"))

indexOf returns -1 if the character isn't found within the string,
otherwise it returns the position index of the found character. If you
test a number as a boolean, it only returns true if the number == 1,
as per this example :

var num:Number;
num = -1;
trace(num==true); // displays "false"
num = 0;
trace(num==true); // displays "false"
num = 1;
trace(num==true); // displays "true"
num = 2;
trace(num==true); // displays "false"


Hope this helps!

cheers
Seb Lee-Delisle
http://sebleedelisle.com

On 01/11/06, Robert Stevens <robs_here at btinternet.com> wrote:
> Seb,
>
> Thanks for your reply.
> Dunno, can't seem to get it working.
>
> Here's example of the code:
> _root.form.my_btn.onRelease = function() {
>         emailAddress = _root.form.email;
>         if (emailAddress.indexOf("@")) {
>                 _root.gotoAndStop("no_error");
>         }
> };
>
> Do I need to specify  'String' in here somewhere. Is
> that it?
>
> Thanks,
>
> Rob
>
>
> --- Seb L <pluginseb at gmail.com> wrote:
>
> > Hi Robert,
> >
> > indexOf should work fine in this case... check for a
> > result of -1 :
> >
> > var mystr:String  = "12345 at 234";
> > var mystr2:String  = "123454t";
> >
> > trace(mystr.indexOf("@"));  // returns 5
> > trace(mystr2.indexOf("@")); // returns -1
> >
> > If that's still not working I suspect you have a
> > referencing problem,
> > make sure you're actually testing the right thing!
> > I'd trace the value
> > to make sure that it's what you should be checking.
> >
> > good luck :-)
> >
> > Seb
> >
> > On 31/10/06, Robert Stevens
> > <robs_here at btinternet.com> wrote:
> > > Hi All,
> > >
> > > An easy one here for many of you I'm sure.
> > >
> > > I have a function set up for a button which
> > includes
> > > an 'if' statement.
> > > I simply need to check if the "@" symbol is
> > present in
> > > a form field.
> > > I've tried the "indexOf" method but it didn't seem
> > to
> > > work.
> > >
> > > Thanks in advance,
> > >
> > > Rob
> > >
> > >
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